Searsboro, Iowa has a population of 155, with a median household income of $58,200.
Current unemployment data for Searsboro.
155
$58,200
3.10%
$191,400
3.40
184.00 Mbps
Searsboro is a small local community located in Iowa. The city has a population that is below the average city population in Iowa, contributing to its local economic activity, housing demand, and infrastructure development. Population size can significantly influence transportation systems, commercial growth, educational services, and employment opportunities within the region.
Searsboro is a notable city in Iowa, offering a mix of population dynamics, economic indicators, and housing trends.
Searsboro has a population of 155, which is below the state average. This suggests a smaller and more localized community environment.
The median household income in Searsboro is $58,200, which is above the state average. This reflects stronger earning potential and economic stability.
The average housing price in Searsboro is about $191,400, making it relatively affordable compared to many cities in Iowa.
The unemployment rate in Searsboro is 3.10%, which is lower than the state average, indicating a relatively strong job market. Searsboro has a lower crime rate than the state average, contributing to a relatively safer living environment.
Compared to other cities in Iowa, Searsboro shows distinct differences in population size, economic activity, and housing affordability, making it a unique case for analysis.
Overall, Searsboro offers a balanced mix of economic conditions, population trends, and housing opportunities within Iowa.
The population of Searsboro is approximately 155.
Searsboro offers a mix of economic conditions, housing affordability, and population size, making it suitable for different types of residents.
The median household income in Searsboro is around $58,200.
The average housing price in Searsboro is approximately $191,400.