Selinsgrove borough, Pennsylvania has a population of 5,736, with a median household income of $55,600.
Current crime rate data for Selinsgrove borough.
5,736
$55,600
4.40%
$168,900
7.90
219.40 Mbps
Selinsgrove borough is a small local community located in Pennsylvania. The city has a population that is above the average city population in Pennsylvania, contributing to its local economic activity, housing demand, and infrastructure development. Population size can significantly influence transportation systems, commercial growth, educational services, and employment opportunities within the region.
Selinsgrove borough, located in Pennsylvania, is a city that reflects important demographic and economic patterns within the region.
Selinsgrove borough has a population of 5,736, which is higher than the state average. This indicates a relatively larger urban presence within Pennsylvania.
The median household income in Selinsgrove borough is $55,600, which is below the state average, indicating moderate economic conditions.
The average housing price in Selinsgrove borough is about $168,900, making it relatively affordable compared to many cities in Pennsylvania.
The unemployment rate in Selinsgrove borough is 4.40%, which is lower than the state average, indicating a relatively strong job market. Selinsgrove borough has a lower crime rate than the state average, contributing to a relatively safer living environment.
Compared to other cities in Pennsylvania, Selinsgrove borough shows distinct differences in population size, economic activity, and housing affordability, making it a unique case for analysis.
Overall, Selinsgrove borough offers a balanced mix of economic conditions, population trends, and housing opportunities within Pennsylvania.
The population of Selinsgrove borough is approximately 5,736.
Selinsgrove borough offers a mix of economic conditions, housing affordability, and population size, making it suitable for different types of residents.
The median household income in Selinsgrove borough is around $55,600.
The average housing price in Selinsgrove borough is approximately $168,900.